20=-0,25x^2-4x

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Solution for 20=-0,25x^2-4x equation: 



20=-0.25x^2-4x

We move all terms to the left:

20-(-0.25x^2-4x)=0

We get rid of parentheses

0.25x^2+4x+20=0

a = 0.25; b = 4; c = +20;
Δ = b2-4ac
Δ = 42-4·0.25·20
Δ = -4
Delta is less than zero, so there is no solution for the equation

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